泰勒考研试题

先做等价无穷小代换。当x→0时,ln (1+x) ~ x,所以原极限=lim(x→0)(3sinx+x?cos(1/x))/((1+cosx)x)= lim(x→0)(3 sinx/((1+cosx)x)+xcos(1/x)/(cosx+1))=

lim(x→0)3 sinx/((1+cosx)x)+lim(x→0)xcos(1/x)/(cosx+1)= 3/2