求考研数学中的极限。急迫的
=lime^x(e^(x？ln(1+1/x)-x)-1)/x
=lime^x(xln(1+1/x)-1)
=lim(xln(1+1/x)-1)/e^(-x)
= lim(ln(1+1/x)+x(-1/x？)/(1+1/x))/-e^(-x)
=lim(1/(x+1)-ln(1+1/x))/e^(-x)
=lim(-1/(x+1)？-(-1/x？)/(1+1/x))/-e^(-x)
=lim-e^x/(x+1)
=-∞
=lime^x(xln(1+1/x)-1)
=lim(xln(1+1/x)-1)/e^(-x)
= lim(ln(1+1/x)+x(-1/x？)/(1+1/x))/-e^(-x)
=lim(1/(x+1)-ln(1+1/x))/e^(-x)
=lim(-1/(x+1)？-(-1/x？)/(1+1/x))/-e^(-x)
=lim-e^x/(x+1)
=-∞